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Mathematics 13 Online
OpenStudy (ashley7777):

sqr3sin2x=cox2x solve for x

OpenStudy (anonymous):

Okay, the first thing you should do is divide both sides by cos(2x).

OpenStudy (ashley7777):

sqr3tan2x=1 tan2x=sqr3/3

OpenStudy (anonymous):

Yes, that's right. I would have personally left it as 1/sqt3 because of the next step: take the inverse tangent of both sides.

OpenStudy (ashley7777):

thanks!!!

OpenStudy (anonymous):

I'm guessing you know the rest? No problem!

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