A bag of fruit contains 3 apples and 2 oranges and 1 banana and 4 pears.Gerald will randomly selected two pieces of fruit one at a time from the bag and not put is back. What is the probability that the first piece of fruit Gerald selects will be a banana and the second piece of fruit will be a pear??
F. 1/25
G. 2/45
H. 1/2
J. 4/9
Please help I'll give a medal!!!
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OpenStudy (anonymous):
@StudyGurl14
OpenStudy (studygurl14):
First find tjhe total amount of fruit.
OpenStudy (anonymous):
10
OpenStudy (studygurl14):
Correct. Now find the amount of bananas.
OpenStudy (anonymous):
1
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OpenStudy (anonymous):
In Circle p, what is the measure of ADB?
OpenStudy (studygurl14):
Correct. now find the amount of pears
@islander691 Please do not spam. Do not post your question in someone else's thread
OpenStudy (anonymous):
lol. srry i jus need help.
OpenStudy (anonymous):
4
OpenStudy (studygurl14):
Tag me to your question. @islander691
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OpenStudy (anonymous):
aight
OpenStudy (anonymous):
In Circle p, what is the measure of ADB?
OpenStudy (studygurl14):
correct. now you need to multiply the probailities of choosing a banana and choosing a pear together. So do this:
\(\Large \frac{1}{10}\times\frac{4}{10}\)
OpenStudy (studygurl14):
I said tag me to your question @islander691
Open your question in your own post, and then tag me by typing @StudyGurl14
OpenStudy (anonymous):
oh ok
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OpenStudy (anonymous):
4/10 or 4/20
OpenStudy (anonymous):
....
OpenStudy (anonymous):
No
OpenStudy (anonymous):
I already got the answer....long time ago..but still thank u