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OpenStudy (anonymous):
please help A box of mass 21 kg sits on an inclined surface with an angle of 10. What is the component of the weight of the box along the surface? A. 203 N B. 59 N C. 36 N D. 113 N
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OpenStudy (shamim):
Weight of 21 kg=mg=21*9.8=?
OpenStudy (shamim):
The component of weight along the surface=mg*sin10=21*9.8*sin10=?
OpenStudy (shamim):
Response plz!!!!!!
OpenStudy (anonymous):
I got 203
OpenStudy (anonymous):
Is that right?
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OpenStudy (shamim):
I think u r not right!!!
OpenStudy (shamim):
Can u tell me Sin10=?
OpenStudy (shamim):
U should calculate it by calculator
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