joint probability thing, writing the latex ...
a device runs until either of 2 parts fail the function of the 2 components in hours is: \[f(x,y)=\frac18(x+y)~:~ x=y=0..2\] what is the probability if fails within 1 hour
i thought we just integrate it, but thats not working for me
maybe i didnt pencil it in right ... .125
\[\frac18\int_{0}^{1}\int_{0}^{1}x+y~dx~dy\] \[\frac18\int_{0}^{1}\frac12+y~dy\] \[\frac18(\frac12+\frac12)=\frac1{32}\]
need to subtract from 1 i think
nope, 1/2 + 1/2 = 1, not 1/4 :)
.125 is fine
i kept getting 1/32 and wondering why :) stupid addition, its to boring to bother with
why is it always the arithmetic
i blame kelly young :) i was to occupied with the girls when they were teaching it i spose
LOL but I wasn't o.0
|dw:1428046342801:dw| http://www.wolframalpha.com/input/?i=1+-+%5Cint_1%5E2%5Cint_1%5E2+%28x%2By%29%2F8+dxdy
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