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Mathematics 27 Online
OpenStudy (anonymous):

Will give medal for explanation. x2 − 16x + ____

OpenStudy (korosh23):

Are you trying to find the blank?

OpenStudy (anonymous):

yeah, sorry for not clarifying.

OpenStudy (korosh23):

No that is fine, well the third number can varry.

OpenStudy (anonymous):

1 was thinking -16 but 1 don't know.

OpenStudy (korosh23):

This form is called quadratic form. Are you trying to change it vertex fom?

OpenStudy (anonymous):

vertex form?

OpenStudy (korosh23):

yes ? do you know what it is ?

OpenStudy (anonymous):

no

OpenStudy (korosh23):

http://static.prometheanplanet.com/images/resources/resource-thumbnails/thumb-nalg2-05-01-0025-diagram-thumb-lg-png.png see this, I am trying to see if it is possible to solve this question using vertex form. However you need to know the third number.

OpenStudy (anonymous):

1 don't think that's what 1'm supposed to do...

OpenStudy (anonymous):

1'm doing perfect square trinomials

OpenStudy (korosh23):

ok let me see

OpenStudy (korosh23):

I solved it, but by guessing and using some common sense. Just tell me is this the thing you are looking for x^2+16x+?

OpenStudy (anonymous):

yes

OpenStudy (korosh23):

ok well I did it like this: \[x^2+16x+?\] \[(x+?)(x+?)\]

OpenStudy (anonymous):

okay

OpenStudy (korosh23):

I told myself x times x is x^2, so ? has to be something to equal 16x

OpenStudy (korosh23):

what times x gives 16x ?

OpenStudy (anonymous):

16

OpenStudy (korosh23):

ok let's plug it in and see if it is right ? \[\left( x+16 \right)\left( x+16 \right)\]

OpenStudy (korosh23):

x^2 + 32x+ 256???!??!!!

OpenStudy (korosh23):

Wow no that is not what we want. we want 16x right?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

wouldn't it be -16?

OpenStudy (korosh23):

No, but think of a number lower than 16

OpenStudy (anonymous):

8?

OpenStudy (korosh23):

Lets plug it in.

OpenStudy (korosh23):

\[(x+8)(x+8)\] x^2 + 16x + 64 Wow the third number is 64!!!

OpenStudy (korosh23):

Awsome you did good man!

OpenStudy (anonymous):

but it's x^2 - 16x

OpenStudy (anonymous):

would it still apply?

OpenStudy (korosh23):

no we have to change something

OpenStudy (korosh23):

|dw:1428170796689:dw|

OpenStudy (korosh23):

Third number is there.

OpenStudy (anonymous):

but it needs to be x^2 − 16x + ____

OpenStudy (anonymous):

the third number is positive

OpenStudy (korosh23):

If you liked my answer, give me a medal, and I would appreciate if you write me a fan testimonial as well. If you need more help, let me know to clarify it for you. :)

OpenStudy (korosh23):

I am sorry (x-8)(x-8) is X^2 - 16x + 64 -8 times -8 is 64. See you are smart ! awsome. :D

OpenStudy (anonymous):

okay thanks.

OpenStudy (korosh23):

Your welcome!

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