Will give medal for explanation. x2 − 16x + ____
Are you trying to find the blank?
yeah, sorry for not clarifying.
No that is fine, well the third number can varry.
1 was thinking -16 but 1 don't know.
This form is called quadratic form. Are you trying to change it vertex fom?
vertex form?
yes ? do you know what it is ?
no
http://static.prometheanplanet.com/images/resources/resource-thumbnails/thumb-nalg2-05-01-0025-diagram-thumb-lg-png.png see this, I am trying to see if it is possible to solve this question using vertex form. However you need to know the third number.
1 don't think that's what 1'm supposed to do...
1'm doing perfect square trinomials
ok let me see
I solved it, but by guessing and using some common sense. Just tell me is this the thing you are looking for x^2+16x+?
yes
ok well I did it like this: \[x^2+16x+?\] \[(x+?)(x+?)\]
okay
I told myself x times x is x^2, so ? has to be something to equal 16x
what times x gives 16x ?
16
ok let's plug it in and see if it is right ? \[\left( x+16 \right)\left( x+16 \right)\]
x^2 + 32x+ 256???!??!!!
Wow no that is not what we want. we want 16x right?
yeah
wouldn't it be -16?
No, but think of a number lower than 16
8?
Lets plug it in.
\[(x+8)(x+8)\] x^2 + 16x + 64 Wow the third number is 64!!!
Awsome you did good man!
but it's x^2 - 16x
would it still apply?
no we have to change something
|dw:1428170796689:dw|
Third number is there.
but it needs to be x^2 − 16x + ____
the third number is positive
If you liked my answer, give me a medal, and I would appreciate if you write me a fan testimonial as well. If you need more help, let me know to clarify it for you. :)
I am sorry (x-8)(x-8) is X^2 - 16x + 64 -8 times -8 is 64. See you are smart ! awsome. :D
okay thanks.
Your welcome!
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