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Mathematics 15 Online
OpenStudy (itsmichelle29):

the inverse of this function please i give medals F(x)=4x-2 / 3

OpenStudy (itsmichelle29):

can you explain it to me step by step

OpenStudy (itsmichelle29):

please

OpenStudy (coconutjj):

switch x and y, then solve for y

OpenStudy (itsmichelle29):

ok so it will be y=4x-2 / 3

OpenStudy (anonymous):

let F(x) = y. y = (4x - 2) /3 To find inverse: swap ALL occurrences of x and y this becomes: x = (4y - 2)/3 isolate y to make it look like the first line. y = F inverse

OpenStudy (itsmichelle29):

then ??

OpenStudy (coconutjj):

x=4y-2/3

OpenStudy (coconutjj):

solve for y

OpenStudy (itsmichelle29):

do i multiply 3

OpenStudy (anonymous):

yes

OpenStudy (coconutjj):

yes... cmon... you know how to do algebra

OpenStudy (itsmichelle29):

like 3 x x = 4y-2 / 3 x3

OpenStudy (anonymous):

yes. isolate y so its by itself

OpenStudy (itsmichelle29):

okay so then i get 3x=4y-2

OpenStudy (anonymous):

yup

OpenStudy (itsmichelle29):

then i add 2 to both sides right

OpenStudy (anonymous):

yes

OpenStudy (itsmichelle29):

which is 4y=3x+2

OpenStudy (itsmichelle29):

now im stuck

OpenStudy (anonymous):

divide both sides by 4

OpenStudy (itsmichelle29):

how ?? i dont get it

OpenStudy (coconutjj):

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