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Physics 9 Online
OpenStudy (anonymous):

A particle with a charge of 0.02 C is moving at right angles to a uniform magnetic field with a strength of 0.6 T. The velocity of the charge is 660 m/s. What is the magnitude of the magnetic force exerted on the particle?

OpenStudy (irishboy123):

Lorentz Force Law: F = q E + qv x B in this case, F = qvB as motion perpendicular to field.

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