Question

Determine the vertex of the following quadratic function and the range of the function.

f(x)= 10(x+1)^2 - 100

Please provide a step by step explanation and the answer.

Answer 1

\(\large {
y=(x-{\color{brown}{ h}})^2+{\color{blue}{ k}}\\
x=(y-{\color{blue}{ k}})^2+{\color{brown}{ h}}\qquad\qquad vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})
}\)

what do you think is the vertex anyway?

Answer 2

The vertex is (-1, -100), right?

Answer 3

yes!