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help! lim x cos x-x^2 / 2x approaches x-> 0
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\[\frac{x\cos(x)-x^2}{2x}\]?
yeah is that one mistry :D
hahah Thanks girls!
you can factor out an \(x\) and cancel first
\[\frac{\cos(x)-x}{2}\]
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@emilyboob misty is just helping lol
Bye!
replace x by 0 and that is done
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