Question

Need clarification on test for divergence--

Answer 1

\[\sum_{n=1}^{\infty}\frac{ e^{n} }{ n^{2} }\]

so I took the e^n/n^2 and found that it approaches infinity as n approaches infinity, but is that enough to conclude that it's divergent?

Answer 2

oops so infinity also means the limit doesn't exist