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Rewrite the equation 2y^2+8y-2x+6=0 in standard form A. (y+2)^2=2(x+1) B. (y+4)^2=x+1 C. (y+2)^2=x+1 D. (y+2)^2=x-3
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2y^2 +8y = 2x - 6
we can divide this by 2
it will be: y^2 + 4 = x - 3
Ok
what u will do next?
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(Y+2)^2?
+
3
??
4?
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D?
Oh ok
i ask u
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