Question

Solve the system of equations.

y = 7x + 43
y = 2x + 13
a.
( -6, 1)
c.
( 6, 1)
b.
( 6, -1)
d.
No solution

Answer 1

@Gummibear127

Answer 2

plug in equation 1 into equation 2

Answer 3

\[(7x + 43)= 2x + 13\]

Answer 4

we want to isolate X so subtract 43 from both sides

Answer 5

13-43=?

Answer 6

Hey it looks like @kidrah69 is already helping you and im not really good with this any way sorry

Answer 7

it says -30

Answer 8

i wanted her to help though

Answer 9

yep thats correct so now we have
\[7x=2x-30\]
add 2x to 7x
2+7=?

Answer 10

@eminem-101 if you want her to help i can stop :)

Answer 11

9

Answer 12

it is fine

Answer 13

ok good so we have
9x=-30 when you divide what do you get?

Answer 14

0

Answer 15

No -30/9 is NOT 0

Answer 16

oh it's -3.333

Answer 17

Why did you add the 2x to the 7x ?? Be careful.

Answer 18

dont you combine like terms?

Answer 19

oh wait you would subtract

Answer 20

right so 7-2

Answer 21

Yes if there is a + between them. You have an equal sign.

Answer 22

5

Answer 23

right so -30/5=?

Answer 24

-6

Answer 25

yep :) now plug that into the 2nd equation
\[y=2(-6)+13\]
solve that

Answer 26

1

Answer 27

\[(7x+43)=2x+13 \]
subtract 43 from both sides to isolate X
\[7x=2x−30\]
subtract 2 from 7
\[5x=-30\]
divide
x=-6
plug in -6 to equation 2
\[y=2(−6)+13\]
y=-1

Answer 28

so whats the final answer and i rewrote that so you can see what we did :)

Answer 29

i got 1 not -1

Answer 30

yeah i accidently put that negative =/ so whats the final answer ? We have
(-6,1)

Answer 31

(-6,1) is the answer right

Answer 32

yep :) xD

Answer 33

that you

Answer 34

that i think you mean thanks
you're welcome ;)

Answer 35

sorry you are right

Answer 36

lol o need to be sorry :P