Question

f(x)=3/x-2 -sqrt x-3
f(19)=
so i solved for F(19) and I got 1/7-4 but i tried typing that into this test I am taking and it said invalid format. Then I combined like terms and i got -27/7 whih was still in the wrong format, so now what?

Answer 1

Do you mean \(\dfrac{3}{x-2}\;or\;\dfrac{3}{x}-2\)? You have written the latter.

Answer 2

3/(x-2-sqrt(x-3) is this the equation?
i get 3/(17-4) =3/13

Answer 3

no the question is 3 divided by x-2 minus the quare root of x-3

Answer 4

try decimal form

Answer 5

-3.8 is what i got

Answer 6

Alright thanks