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@Michele_Laino
here, we can write: \[\large {x^2} - 2x - 3 = {x^2} - 2x + 1 - 1 - 3 = ...?\]
4?
hint: \[{x^2} - 2x - 3 = {x^2} - 2x + 1 - 1 - 3 = {\left( {x - 1} \right)^2} - 4\]
\[\large {x^2} - 2x - 3 = {x^2} - 2x + 1 - 1 - 3 = {\left( {x - 1} \right)^2} - 4\]
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so we can rewrite your equation,as follows: \[\begin{gathered} {\left( {x - 1} \right)^2} - 4 = 0 \hfill \\ {\left( {x - 1} \right)^2} = 4 \hfill \\ \end{gathered} \]
\[\left( x+?^{2}=4 \right)\]
the requested number is: \[ - 1\]
yes!
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