Find the radius of a circle in which a 48cm chord is 8 cm closer than a 40cm chord
Does any one know how to draw and walk me through the problem I know the answer I just need help knowing how to do the problem and all the theorems that go along with it.
Thank You So much for your help

Question

Find the radius of a circle in which a 48cm chord is 8 cm closer than a 40cm chord
Does any one know how to draw and walk me through the problem I know the answer I just need help knowing how to do the problem and all the theorems that go along with it.
Thank You So much for your help

mathstudent55 · Answer

The 48 cm chord is 8 cm closer to what? To the center of the circle?

mathstudent55 · Answer

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mathstudent55 · Answer

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$20^2 + (x + 8)^2 = r^2$

$24^2 + x^2 = r^2$