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Algebra 6 Online
OpenStudy (anonymous):

How may permutations of the word “spell” are there?

OpenStudy (mathstudent55):

Must they be different from each other?

OpenStudy (anonymous):

no of permutations= \[\frac{ 5! }{ 2! }\]

OpenStudy (anonymous):

no. of L's = 2 hence divide from 2!

OpenStudy (anonymous):

see, to make a 5-letter word , 5 places are to be filled ___ ___ ___ ___ ___ 1st 2nd 3rd 4th 5th the first place can be filled in 5 ways (s,p,e,l,l) 2nd place in 4 ways. 3rd place in 3 ways. 4th place in 2 ways. 5th place in 1 way. now , ther are 2L's. hence total no. of words that can be formed=(5*4*3*2*1) / 2*1

OpenStudy (anonymous):

you can visualize that how the things happen and how different word are formed by fundamental principle of counting.

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