The city is installing fencing around a rectangular space for a new dog-walking park. The length of the rectangle is 2.25 times its width. If the length measures 150 yards, what will be the perimeter of the dog-walking park?
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OpenStudy (anonymous):
I got 433.33 Yards but can't figure out how they got that answer
OpenStudy (anonymous):
so 2*150=300 and then what?
OpenStudy (anonymous):
sorry, its not correct
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
@Michele_Laino
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OpenStudy (michele_laino):
we have:
width= length/5= 150/2.25=...?
OpenStudy (anonymous):
so 150 divided by 2.25 and then what?
OpenStudy (michele_laino):
the requested perimeter is:
\[\large L + W + L + W = 150 + W + 150 + W = ...?\]
where:
\[\large W = \frac{L}{{2.25}} = \frac{{150}}{{2.25}} = ...?\]
OpenStudy (anonymous):
150
OpenStudy (michele_laino):
we have:
\[\large W = \frac{L}{{2.25}} = \frac{{150}}{{2.25}} = 66.667\]
so:
perimeter is:
\[\large 150 + W + 150 + W = 300 + 66.667 + 66.667 = ...?\]
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