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Give the equivalent numerator if the denominator is (x-2)(x-1)(x-6). 2x² - 10x + 12 2x² - 14x + 12 2x² - 14x - 10
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\[\frac{ 2 }{ x-2 }\]
@Owlcoffee
\[\frac{ 2 }{( x-2) }\] Analogically as the last problems, we multiply both numerator and denominator by the expression we require as equal denominator: \[\frac{ 2(x-1)(x-6) }{ (x-2)(x-1)(x-6) }\] All you have to do is apply the distributive property on the numerator of this last fraction.
How?
\[2(x-1)(x-6)\] \[(2x-2)(x-6)\] \[2x^2-12x+2x+12\] \[2x^2 -10x + 12\] And that's the numerator we were looking for.
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