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Use the quadratic equation y = x2 – 6x + 9. Where does the vertex of the parabola lie?
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Formula to find the x-coordinate of the vertex: \(\sf \dfrac{-b}{2a}\)
Your equation is in the form of: ax^2 + bx + c
So in this case, 'b' is -6 and 'a' is 1.
\(\sf \dfrac{-b}{2a}\) \(\sf \dfrac{-(-6)}{2(1)}\) Simplify
-1 * -6 = ? 2 * 1 = ?
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