Question

Two equations are given below:

a − 3b = 16
a = b − 2

What is the solution to the set of equations in the form (a, b)?

Answer 1

well substitute

\[(b-2) − 3b = 16 \]
it already tells u what a equals

Answer 2

solve that.....

Answer 3

(−2, −6)
(−7, −9)
(−11, −9)
(−12, −10)

Answer 4

what is the ???

Answer 5

refresh

Answer 6

um is it 1b=16?

Answer 7

wait so then b=16? what?

Answer 8

incorrect
\[b-2-3b=16\]
whats b-3b?

Answer 9

3b?

Answer 10

i dont know this

Answer 11

1-3?

Answer 12

2

Answer 13

no
1 MINUS 3

Answer 14

not 3-1

Answer 15

-2* sorry

Answer 16

its oky :)
since we have what is 16+2?

Answer 17

18

Answer 18

whats -2/18?

Answer 19

-0.11

Answer 20

18/-2

Answer 21

-9

Answer 22

\[(b-2)-3b=16 \]
\[b-2-3b=16\]
subtract b
\[b-3b=-2b\]
you have -2b
\[-2b-2=16\]
add 2 to both sides to isolate b
\[-2b=18\]
divide to get b value
b=-9
plug it in the other equation
\[a=b-2 \]
plug -9
\[a=-9-2\]
whats -9-2?
a=?

Answer 23

-11

Answer 24

am i correct?

Answer 25

yep :)

Answer 26

so then whats the answer?
?

(−2, −6)
(−7, −9)
(−11, −9)
(−12, −10)

Answer 27

u tell me
if
b=-9
a=-11
what is the answer?

Answer 28

c

Answer 29

the 3rd one

Answer 30

good job :)

Answer 31

thank you so much :)

Answer 32

you're welcome :)