Question

Help with Polynomial graphing
Please help

Answer 1

I f I have the x intercepts 8,0 and 22,0 and 32,0 and 40,0

Answer 2

and my y intercept is 0,250

Answer 3

and the equations maximums and minumums are 14,200 and 26,-50 and 34, 50

Answer 4

how would i do that?

Answer 5

Normally you would set it up like this:
y=(x-8)
since you know that at x=8 the y is 0
then add other x-intercepts the same way, knowing that x=22 , x=32 and x=40 are x-intercepts.

y=(x-8)(x-22)(x-32)(x-40)

Answer 6

how would I incoroporate all of the extra points

Answer 7

how would I get the right a value?

Answer 8

(continuing my post)
your function is going through (0,250) - that is - the function shifted 250 units up from the origin.

So,
\(\large\color{black}{ \displaystyle y=(x-8)(x-22)(x-32)(x-40)\color{red}{+250} }\)

Answer 9

the right value for what ?

Answer 10

the A value

Answer 11

and where do this many maximum and minimum values come from?
are they local max and local min ?
(should be so, since there is no interval boundary)

Answer 12

well, at least the maximum approaches infinity.

Answer 13

the maximums and minumums are the turning pints on the graph

Answer 14

there are 4 turning points

Answer 15

yes, that is what I though... maybe we can check this function as I did it, and see how it goes.

Answer 16

I will graph what I did on desmos.

Answer 17

and the domain is [0,40]

Answer 18

me too

Answer 19

The equation seems to go on forever though

Answer 20

oh, the domain is [0,40]
we need to expand this function
y=(x−8)(x−22)(x−32)(x−40)
then to shift it to the y-intercept (0,250)

Answer 21

wait what are the symbols you typed?

Answer 22

minuses supposed to be

Answer 23

heres a picture of the graph

Answer 24

kind of hard to see that

Answer 25

ill try to get some better light on it. one sec

Answer 26

shoot it still isnt coming out clear

Answer 27

can you kinda see the graph??

Answer 28

it is sideways

Answer 29

yeah

Answer 30

sorry about that

Answer 31

heres a better picture

Answer 32

and what do you want to know about this function ??

Answer 33

How would I get the function to go through all the maximums and minimums

Answer 34

I tried getting the correct a value by inserting the y intercept but didn't get me the right maximums and minimums obivously

Answer 35

how would I get the equation so it would go through all the points given

Answer 36

is it possible?!?

Answer 37

I was thinking about
y=(x-8)(x-22)(x-32)(x-40)+225030
but I am not sure

Answer 38

apologize

Answer 39

ok thanks Im going to graph it and see how it works

Answer 40

thanks so much by the way

Answer 41

Thanks I think I'm good!