Question

help pls

Answer 1

\[\sum_{i=0}^{3}i^3= \left( \frac{ n(n+1) }{ 2 } \right)^2\]

Answer 2

I mistyped i as n. i=0 should be n=0

Answer 3

A. 0^3 + 3^3

B. 0^3 + 1^3 + 2^3

C. 1^3 + 2^3 + 3^3

D. 0^3 + 1^3 + 2^3 + 3^3

Answer 4

Oh okay, so if you expand them you write out all the numbers before adding them together. You start with the i number so 0^3 all the way to 3^3. Whats in between?

Answer 5

Can I f*** u tits @saarupp

Answer 6

@The_Beast98 gtfo