Mathematics
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OpenStudy (anonymous):
HELP AWARDING METAL!!
Find all solutions to the equation.
sin2x + sin x = 0
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Nnesha (nnesha):
do-you-know-sin-cos-properties-reciprocal-functions??
sin^2=??
OpenStudy (anonymous):
tbh, no.
OpenStudy (henriquerb):
sin (2x) = sinxcosx + cosxsinx = 2sinxcosx
OpenStudy (anonymous):
thanks :)
Nnesha (nnesha):
i-guess-2-is-exponent-right?
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OpenStudy (henriquerb):
sin(x)(1+2cosx).
So, sin(x)(1+2cosx)=0 when sin(x)=0 or 1+2cosx=0
OpenStudy (anonymous):
That's it?
OpenStudy (anonymous):
yep
OpenStudy (henriquerb):
Well, do you think you can handle from there?
OpenStudy (anonymous):
No not really?
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OpenStudy (henriquerb):
Ok, so 2cosx = -1 and sinx=0
OpenStudy (anonymous):
yea?
OpenStudy (henriquerb):
Now you have to find the x on those equations.
OpenStudy (henriquerb):
sin x = 0 is easy, just npi, with n integer.
OpenStudy (anonymous):
Oh, ok
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OpenStudy (henriquerb):
2cosx=-1 so cosx=-1/2
so x = 2pi/3 + 2pi n, with n integer
or
x=4pi/3 + 2pi n, with n integer
OpenStudy (anonymous):
Oh, so that's it?
OpenStudy (henriquerb):
I think that's it. If i didn't make any mistakes.
OpenStudy (anonymous):
Wow, your like a genius.
OpenStudy (anonymous):
Thank you :::)
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OpenStudy (henriquerb):
I'm surely not.
You're welcome. =)
OpenStudy (anonymous):
Find all solutions in the interval [0, 2π).
2 sin2x = sin x