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Calc 3 problem... Find the slope of the tangent to the curve of the intersection of the cylinder 6z=3 sqrt(20-x^2) and the plane y=9 at the point (2,9,2)
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Nothing - not sure how to even start it
I'm guessing to start off with finding an equation of the tangent line..
Don't know how to get slope or how the "y=9" fits into this
First note that this isn't really a cylinder because its cross-sections are not circular, but rather elliptical. (Still a quadric surface, though.) \[6z=3\sqrt{20-x^2}~~\implies~~4z^2+x^2=20\] Let's draw this in the \(x\)-\(z\) plane: |dw:1428592568475:dw|
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