Question

i will MEDAL PLZ help

Solve.

8y – 24 > –16

A.
y > –5

B.
y > –1

C.
y > 1

D.
y > 5

Answer 1

First Step: Add 24 to both sides:\[8y - 24 + 24 > -16 + 24\]
Which equals:\[8y > 8\]

Answer 2

ok

Answer 3

Now, we divide both sides by 8:\[\left(\begin{matrix}8y \\ 8\end{matrix}\right)\left(\begin{matrix}8 \\ 8\end{matrix}\right)\]

Answer 4

Which gives you the answer:\[y > 1\]

Answer 5

(1y) (1)???

Answer 6

oh ok

Answer 7

8y divide by 8 only leaves y because the 8's cancel out

Answer 8

got it

Answer 9

and on the other sides of the equation, 8 divided by 8 leaves you with 1

Answer 10

ok so what do we do with the 24 and -16

Answer 11

The first step we added +24 to both sides which canceled the 24's on the left side of the equation, and -16 + 24 is 8