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Mathematics 20 Online
OpenStudy (anonymous):

Help! With Approximation's of Irrational's!!!!

OpenStudy (anonymous):

i can try

OpenStudy (superman499):

i can help

OpenStudy (anonymous):

OpenStudy (superman499):

u got it correct it is A

OpenStudy (anonymous):

The reason A is right is that \(3^2\) is 9, and \(4^2\) is 16, so \(\sqrt{12}\) must lie somewhere in that range.

OpenStudy (superman499):

make u a number line

OpenStudy (superman499):

that is how u find ur answer

OpenStudy (anonymous):

Can u Help with some more please?

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