Question

write the product as a trinomial
(3r - 4) (r + 8)
A. 3r^2 - 32
B. 3r^2 - 28r - 32
C. 3r^2 + 20r - 32
D. 4r^2 + 4r - 32
(will medal)

Answer 1

So we need to Simplify:\[(3r + -4)(r+8)\]

Answer 2

\[(3r)(r)+(3r)(8)+(-4)(r)+(-4)(8)\]
Which equals:
\[3r^2+24r-4r-32\]

Answer 3

Now 24r-4r = 20r so that gives you the answer:\[3r^2+20r-32\]