Question

Help please,
Find the magnitude and direction angle (to the nearest tenth) for the given vector. Give the measure of the direction angle as an angle in [0,360deg].
<-5 ,12>
(I found the mag. to be 13 and the direction angle I'm unsure of do I subtract -67.4 degrees by 180 degrees to get the direction angle? I got 112.6 degrees)

Answer 1

ok so your magnitude and method of obtaining the angle are correct. just look at the visual to determine the rest. so it's 90 degrees in each quadrant right? and counter clockwise is positive. so 180 degrees minus 67.4 degrees looks like it is the answer.
Your answer is correct. 13 @ 112.6º

Answer 2

Thank you for your explanation