Question

Find the vertex of the parabola by completing the square.
y=x^2+4x-8

Answer 1

Use the following formula for both x-vertex and y-vertex.
\[x _{v}=-\frac{ b }{ 2a }\], where b is the value attached to the x - variable and a is the value attached to the x^2 variable.
\[y=\frac{ \Delta }{ 4a}\] or \[y=\frac{ b ^{2}-4ac }{ 4a }\].
Once you find them, plot as coordinates
\[(x _{v},y _{v})\], where v means vertex.
Think you can carry on from here?

Answer 2

Yeah thanks

Answer 3

No problem.
Medal please?