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The prism has a surface area of 1312 mm2. What would the surface area of the prism be if each dimension were halved?
So each dimention is 32 by 8 by 10 so the surface area=2 times(8 times 10)+(2 times (32 times 10))+(2 times (8 times 32))=2 times 80+2 times 320+2 times 256=1312 if halved just divide each by 2 (2 times 4 times 5)+(2 times 16 times 5)+(2 times 4 times 16)=(2 times 20)+(2 times 80)+(2 times 64)=40+160+128=328 the new surface area is 328 mm^2
or just divide by 4 1312/4=328 you are halving each side and each of the 6 sides and thus quartered so the final answer is quartered also
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