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Conditional probability: A teacher gave his class two quizzes; 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first quiz also passed the second quiz?
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let A=first quiz is passed let B=second quiz is passed we then have that the probability of the second quiz being passed, given that the first is passed is\[P(B|A)=\frac{P(A\cap B)}{P(A)}\]
Right, so 75% passed both quizzes
well, no, it says in the problem that 60% passed both quizzes
pardon me, 75% who passed the first quiz also passed the second
correct :)
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Thanks a bunch!
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