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OpenStudy (anonymous):
how to complete the identity for tan(pi-x)=?
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OpenStudy (anonymous):
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OpenStudy (anonymous):
how to complete the identity for tan(pi-x)=?
OpenStudy (anonymous):
\[\tan(\pi-x)=\frac{\sin(\pi-x)}{\cos(\pi-x)}=\frac{\sin \pi\cos x-\sin x\cos \pi}{\cos\pi\cos x+\sin \pi\sin x}=\cdots\]
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