The inside diameter of a randomly selected piston ring is a random variable, with mean value 12cm and standard deviation 0.04cm.
(i) if µ is the sample mean diameter for a random sample of n=16 ring , then obtain the mean and standard deviation of µ.
(ii)if the sample size is n=64 rings, then the mean and standard deviation of x.
(iii)obtain P[ /µ-2\ ≤ .01] when n=16 and p[/µ-12˂.01] when n=64. Comment on the result.

Question

The inside diameter of a randomly selected piston ring is a random variable, with mean value 12cm and standard deviation 0.04cm.
(i) if µ is the sample mean diameter for a random sample of n=16 ring , then obtain the mean and standard deviation of µ.
(ii)if the sample size is n=64 rings, then the mean and standard deviation of x.
(iii)obtain P[ /µ-2\ ≤ .01] when n=16 and p[/µ-12˂.01] when n=64. Comment on the result.

anonymous · Answer

please help me in solving this

anonymous · Answer

is there anyone who can help me??