Question

Is x^-5+cos(2x) even, odd, or neither?

Answer 1

replace x by -z and see what you get

Answer 2

The sum of an odd function and an even function is neither even nor odd

Answer 3

So I would do -x^-5+cos(-2x)? And then it would be neither?

Answer 4

\[(-x)^{-5}= - x^{-5}
\]
So the first function is odd

Answer 5

\[
\cos( -2 x) =\cos(2x)
\]
So the second function is even

Answer 6

So their sum is neither

Answer 7

Did you get it?

Answer 8

Yes thank you!

Answer 9

YW