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Find the vertex, focus, directrix, and focal width of the parabola. \(-\dfrac 1{40}x^2 = y\)
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I know the vertex is 0, 0 and I know that something is -10, but i'm not sure if it is the focus or directrix
First remember that focus is a "point" and directrix is a "line"
Okay, so it would be the focus that is 0, -10?
Yes focus is (0, -10)
yay! how would I go about finding the directrix and focal width?
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directrix is \(y = -(-10)\) which is same as \(y = 10\)
and the focal width is 40?
Yep!
:D Thanks!
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wow!
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