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y=x^2-2x-5 What are the two x intercepts?
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no
Hint: if we set x=0, what do you get?
Hint: if we set y=0, what do you get?
What's the point in first hint?
I thought tha also the y-intercept was requested @geerky42
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you need to solve x^2 - 2x - 5 = 0
the 2 roots you get are the 2 intercepts
A parabol can interce[t the x axis in two places. When do you intercept the x axis? When y = 0. Therefore, you need to set y = 0 to find the x-interxepts
this equation won't factor so you need to use either the quadratic formula or completing the square
because I know the vertex is (1,-6) but im just lost after that
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The vertex has nothing to do here. To find x-intercepts, you just set \(y = 0\), then solve for x
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