Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (ohohaye):

Please help me

OpenStudy (ohohaye):

OpenStudy (anonymous):

graph it

jimthompson5910 (jim_thompson5910):

see page 2 http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf

OpenStudy (mayankdevnani):

@ohohaye \[\large \bf \cos2x=2\cos^x-1\]

OpenStudy (ohohaye):

Wait, so it is true?

OpenStudy (mayankdevnani):

OpenStudy (mayankdevnani):

yup ! @ohohaye

OpenStudy (ohohaye):

ok, thank you

OpenStudy (mayankdevnani):

your welcome :)

jimthompson5910 (jim_thompson5910):

OpenStudy (anonymous):

shouldn't it be false?

OpenStudy (anonymous):

I graphed both functions and they were different

OpenStudy (mayankdevnani):

yes, it should be !

OpenStudy (mayankdevnani):

oh ! i am really sorry @ohohaye this is FALSE

OpenStudy (ohohaye):

Wait but, you told me that it was True

OpenStudy (mayankdevnani):

\[\large \bf \cos2x=2\cos^2x-1\] \[\large \bf 2\cos^2x=1+\cos2x\] \[\large \bf \cos^2x=\frac{1+\cos2x}{2}=\color{red}{Answer}\]

OpenStudy (mayankdevnani):

sorry... @ohohaye i don't know how i said TRUE ?

OpenStudy (mayankdevnani):

thank you for correcting my mistake ! @10115658

OpenStudy (ohohaye):

its ok, thanks everyone who helped me

OpenStudy (mayankdevnani):

:)

OpenStudy (anonymous):

No problem, simple mistake

OpenStudy (anonymous):

How about a medal lol

OpenStudy (mayankdevnani):

lol i don't care for MEDALS !

OpenStudy (anonymous):

I'm one away from a title haha

OpenStudy (mayankdevnani):

I TRIED MY BEST !

OpenStudy (anonymous):

Thank you kindly

OpenStudy (mayankdevnani):

no problem :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!