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4^x+8=7: Solve & express in terms of natural logarithms. WILL MEDAL!
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subtract 8 from both sides, and take a natural log. you get no solution
ALSO, for 4^x+8=7 to be true, 4^x must =-1 and no exponent will make a pos. number to a negative number.
is that \[\huge\rm 4^{x+8} = 7\] ??
that could also be it:)
Uhh ok lemme work this out real quick. & Yes @Nnesha it is!
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yes so you can change exponential to log form |dw:1428867328995:dw|
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