Might be a dumb question:
Hooke’s Law is F = -kx. Spring A and spring B have spring constants kA
and kB, respectively. If kA = 3kB, what is the relationship of the forces, FA and
FB, to each other, for the same displacement in each spring (x)?
a) FA = FB
b) 3FA = FB
c) FA = 3FB
d) FA = -3FB

Question

Might be a dumb question:
Hooke’s Law is F = -kx. Spring A and spring B have spring constants kA 
    and kB, respectively. If kA = 3kB, what is the relationship of the forces, FA and 
    FB, to each other, for the same displacement in each spring (x)?
a) FA = FB 
	b) 3FA = FB
	c) FA = 3FB
	d) FA = -3FB

anonymous · Answer

the negative is throwing me off! so -3FB=-FA....... I am guessing C??

anonymous · Answer

That's correct.
$$F_A=-k_Ax=-3k_Bx=3F_B$$

anonymous · Answer

thanks

anonymous · Answer

yw