Question

Find the coordinates of the vertex, focus, ends of latus rectum annd the equation of the directrix.
a. y^2=8x
b. x^2=12y
c. y^2=-11x
d. x^2=-6y
e. (y-5)^2 = 4(x+1)
f. (x-7)^2 = -10(y+3)

Answer 1

how to solve this?

Answer 2

@amistre64

Answer 3

@mathmath333

Answer 4

try to write equation in these form \(y = a(x – h)^2 + k\) where

vertex will be \((h,k)\)

Answer 5

see if it makes sense

Answer 6

can we solve letter a. i dont know -.- bzzz..

Answer 7

\( y^2=8x\) ,this is a little different from standard quadratic equation ,

where \(y^2\) is squared instead of \(x\)

\(x=\dfrac{y^2}{8}=\dfrac{1}{8}(y-0)^2+0\)

here as \((h,k)=(0,0)\) vertex is \((0,0)\)