Mathematics
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OpenStudy (thedj4jc):
PLEASE HELP!!!!!!
Find the square root of 25 over 49.
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OpenStudy (thedj4jc):
2. Simplify the square root of 36a^10b^2
OpenStudy (thedj4jc):
Answer options for the first problem
12
0.7142857
5/7
0.510204
OpenStudy (thedj4jc):
2.
6a^5b^5
6a^5b
6ab^5
OpenStudy (anonymous):
Is it \(\dfrac{\sqrt{25}}{49}\)
OpenStudy (anonymous):
Or is it \(\sqrt{\dfrac{25}{49}}\)
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OpenStudy (thedj4jc):
The second one, yes!!
OpenStudy (anonymous):
Oh, just find the square roots of the numbers.
Square root of 25 = ?
Square root of 49 = ?
OpenStudy (thedj4jc):
5 and 7
OpenStudy (thedj4jc):
Thank you!!
Do you have any idea on the second problem?
OpenStudy (anonymous):
Yes, so we have:
\(\sf \dfrac{5}{7}\)
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OpenStudy (thedj4jc):
Yes! Thank you!!
OpenStudy (anonymous):
Yep, find the square root of 36.
OpenStudy (thedj4jc):
6
OpenStudy (anonymous):
And we divide the exponents by 2.
OpenStudy (anonymous):
Yep.
\(\sf a^{10} \rightarrow a^{10 \div 2}\)
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OpenStudy (anonymous):
\(\sf b^2 \rightarrow b^{2 \div 2}\)
OpenStudy (thedj4jc):
So, that would be B. Cause 10 divided by 2 equals 5 and 2 divide by 2 equals 1.
OpenStudy (anonymous):
Yep, you got it.
\(\sf 6a^5b\)