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Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n)=1+(n-1)(-4.1) 1, –15.4, –40 –4.1, –15.4, –36.9 1, –11.3, –35.9 0, –12.3, –36.9
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To find first term replace n with 1 and evaluate
would it be C @myininaya
\[A(n)=1+(n-1)(-4.1) \\ A(1)=1+(1-1)(-4.1)=1+0=1 \\ A(2)=1+(2-1)(-4.1)=?\]
I don't think that will output any of your choices
are you sure you wrote your problem correctly?
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oh fourth term
you can find the fourth term by replacing n with 4
and then tenth term can be found by replacing n with 10
so yeah that seems right
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