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What is the square root of 252 in simplified radical form?
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sqrt252 ghere the biggest perfect square number is 36. so sqrt(36*7)=sqrt(6*6*7)=\[6\times \sqrt{7}\]
could u check my other answers please
@AlexandervonHumboldt2
yes
is the \[\sqrt{28}\] approximated to the nearest tenth? 5.3
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@AlexandervonHumboldt2
yes
Thanks
Is the \[\sqrt{144}\] approximated to the nearest tenth? 10.7
no this is a perfect square number sqrt144=12
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