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\[4-3x \le2x+6\]
1. Simplify both sides to get:\[-3x + 4\le 2x+6\]
2. Subtract 2x from both sides:\[-3x + 4 -2x \le 2x + 6 -2x\] Which equals:\[-5x + 4 \le 6\]
3. Subtract 4 from both sides:\[-5x + 4-4 \le6-4\] Which equals: \[-5x \le 2\]
4(Last Step). Divide both sides by -5: \[\left(\begin{matrix}-5x \\ -5\end{matrix}\right) \le \left(\begin{matrix}2 \\ -5\end{matrix}\right)\]
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Which gives you the answer:\[x \ge \left(\begin{matrix}-2 \\ 5\end{matrix}\right)\]
Thanks!
Your Welcome
Can you help with some more?
i'll try
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find the length of leg x on the right triangle.
IDK sorry :(
Ugh its okay!
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