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Please kindly check my answer :)
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\[\sqrt{6x-2}-7=-3\]
Is it true about the vaule of x that it is supposed to be 3?
I think so right
could you actually help me with another question :)
I believe so Because it would turn into 6x-2=16 6x=18 X=3
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Sure
\[\sqrt{98x ^{8}y ^{5}z ^{40}}\]
what is it in its lowest terms? how do i simplify it
Just a sec, let me pull this up on my laptop instead of my ipad so I can type it better
Cool :)
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\[\sqrt{2}\sqrt{49}\sqrt{x^4}\sqrt{x^2}\sqrt{y^5}\sqrt{z^4}\sqrt{z^10}\] from there you should be able to simplify it the rest of the way
The last one should be sqrt(z^10)
Thank you :)
You're welcome!
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