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use integer values of x from -3 to 3 to graph the equation y = -2x^2 + 3
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Two things to look at. its leading coefficient and constant leading coefficient is -2, so since it is negative, this parabola opens down, right?
and for constant, it is 3, so we can see that at x=0, y is 3
it has point \((0, 3)\)
is it A. @geerky42
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Correct
Thanks : )
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