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@ajanijones
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@ajanijones @SolomonZelman
I think it is \[\frac{ 1 }{ 10 }\]
@campbell_st
so if you have the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 how many are even... (divisible by 2) P(divisible by 2) = number of possibles/total number of choices
@TheSmartOne i'm I right?
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@TheSmartOne
@jagr2713
You are correct :)
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