Question

Digital electronic help

Answer 1

these area bunch of shift registers and d-flip flops but im not sure how this works

Answer 2

i dont even know what the switches are for

Answer 3

@dan815 @ganeshie8

Answer 4

Sorry i do not have an application for ms12 files

Answer 5

do you know how flipflops work though?

Answer 6

A flip-flop or latch is a circuit that has two stable states and can be used to store state information. A flip-flop is a bistable multivibrator. The circuit can be made to change state by signals applied to one or more control inputs and will have one or two outputs. It is the basic storage element in sequential logic. Flip-flops and latches are a fundamental building block of digital electronics systems used in computers, communications, and many other types of systems.

Answer 7

Does that help you?

Answer 8

lol not really, but it's okay, i need help on the actual wiring xD

Answer 9

hmmm okay can you link a different file type than ms12?

Answer 10

i mean if you can visually show me how a shift register works i can probably wire it myself

Answer 11

@dtan5457 if you are willing to download another application I promise it will help you

Answer 12

Here this may help @dtan5457 -> http://www.allaboutcircuits.com/vol_4/chpt_12/1.html

Answer 13

If you have the bit string ABCDEFG Right shift does GABCDEF and left shift does BCDEFGA

Answer 14

how about I upload a screen shot?

Answer 15

@dtan5457 Refer to the website i provided it could possibly help you.

Answer 16

try logism http://www.cburch.com/logisim/download.html

Answer 17

anyways 0001 right shifted would become 1000 and left shifted would become 0010

Answer 18

note that this is analogous somewhat to dividing by ten and multiplying by 10 respectively.

Answer 19

There is a difference between ARITHMETIC shift and LOGICAL shift, which I forgot to mention.
for arithmetic shift if you had
0101 1011 and you shifted right you would get 0 1011 0110 if you shifted left you would get 0101 101
for logical shift if you had 0101 1011 and you shifted right you would get 1010 1101
if you shifted left you would get 1011 0110

Answer 20

@dtan5457 please let us know if we can help you further. Thanks.

Answer 21

yeah, i got my friend to send me his working file, so i'll get a screen shot of it to see if you can explain how the particular set up works

Answer 22

what this is suppose to be is some sort of burglar alarm like system. there is a nand gate as a combination to stop the light on the first flip flop...something like that. not sure how it completely works though

Answer 23

@inkyvoyd

Answer 24

@DivineSolar

Answer 25

Seems inky went offline. He would have been better to help you with that.

Answer 26

Try tagging in some moderators.

Answer 27

@TheSmartOne

Answer 28

I'm not a moderator, and I have no clue whatsoever. lol

Answer 29

Do you know any one who knows this stuff? I only know dan and ganashie

Answer 30

They both aren't here atm xD

Answer 31

hmm, not sure but maybe @wio ?

Answer 32

Sorry i do not.

Answer 33

@satellite73

Answer 34

First let's look at the NAND.
U2A's Q
U3A's not Q
U4A's Q
U5A's not Q
U6A's Q

If any of these signals are 0, then the NAND gate sends a 0
When the NAND gate sends a 0, then U1A turns off.

Answer 35

The clocks are connected to S4.
Ultimately when this switched is turned off and then back on, it shifts all of the bottom d flip flops to the right. The leftmost flip flop gets its input from the state of S2.
So S2 and S4 allow a person to set enter a code.

S3 will clear all of the bottom d flip flops, which basically just clears the input.

Answer 36

S5 and S1 will operated U1A the same way that S2 and S4 operated on U2A.

However, just as the S3 key will always turns out the bottom d flip flops, the result of the NAND gate being off will always turn turn off U1A

Answer 37

Ultimately, S2 and S4 are used to set the codes, that can turn off U1A

S3 is used to clear out the codes

S5 and S1 are used to turn U1A back on

Answer 38

Hello, what you have here is a shift register

Answer 39

you should look at the timing diagram to understand the behavior

Answer 40

Here is a simpler version of your circuit, i changed it so it all depended on just 1 flipflop's clock

Answer 41

http://prntscr.com/6tyocf