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quick adv algebra question
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\[\sqrt[5]{1215}= ?\]
4.139
thanks i know what the decimal is i need someone to EXPLAIN to me step by step reduction to RADICAL form
hint: \[\large 1215 = {3^5} \times 5\]
since: \[1215 = 135 \times 9 = 15 \times 9 \times 9 = 3 \times 5 \times 9 \times 9\]
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Applying the hint given above you can pull out a three from the radical. Thus simplifying it to\[3\sqrt{5}\]
better is: \[\large 3\sqrt[5]{5}\]
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