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OpenStudy (anonymous):
Sum with floor and exponential
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OpenStudy (anonymous):
\[\sum_{n=1}^{10}\lfloor n^3 \rfloor\] How would you solve this?
OpenStudy (rational):
floor of an integer is integer itself
OpenStudy (rational):
\[\sum_{n=1}^{10}\lfloor n^3 \rfloor = \sum_{n=1}^{10} n^3 = \left(\frac{10(10+1)}{2}\right)^2\]
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